Introduction During this experiment, the mass of copper was weighed in grams. It was measured with sodium hydroxide, sulfuric acid, zinc, hydrochloric acid, methanol, and acetone. The main instruments used in this experiment was a balance, beaker, stirring rod, evaporating dish, wire gauze, ring stand, graduated cylinder, copper wire, nitric acid, hydrochloric acid, water, sodium hydroxide, zinc, sulfuric acid, and a hot plate. By finding the raw data, the percent recovered was able to be calculated. Theory The equation that was used in this experiment is % recovered = 100% X m/m0. M = mass of copper recovered and m0 = mass of original copper sample. In order to get the percent recovered, the mass must be determined. After determining the mass, you have to multiply 100% by the mass of the copper recovered divided by the mass of the original copper sample. Experiment 1. …show more content…
Wash the solid with 10 mL of acetone. Decant the liquid. 14. Evaporate the remaining acetone. 15. Dry the evaporating dish. Wait for the dish to cool off then weigh it with the product. Mass of copper wire .2654g Sodium Hydroxide 45mL Sulfuric Acid 25mL Zinc 3.0g Hydrochloric acid 15mL Methanol 10mL Acetone 10mL Calculations In order to find the percent recovered, 100% was multiplied by .2285g divided by .2654g = .086. Mass of copper (beginning) .2654g Mass of copper recovered .2285g Color of Copper oxide Black Conclusions The first attempt of this experiment was unsuccessful because the solution did not turn black after putting the nitric acid into the copper wire. It could have been because there were too much nitric acid that was added which caused it to stay blue instead of changing to black. After retrying the experiment, the results that were received were successful. The percent recovered found in this experiment was .086. In order to find the percent recovered, the mass of the copper had to be measured. The main purpose of doing this experiment was to find out the percent
To calculate the percentage of Cu, we divided the final mass of the penny 0.09 and the initial mass of 2.47 and multiplied by 100. To calculate the percentage of Zn, we divided the final mass of the penny 2.38 and the initial mass of 2.47 and multiplied by 100. During the experiment the hydrochloric acid donated its hydrogen ions in the reaction and then the chloride ions reacted with the zinc ions in the solution. Thus, the zinc dissolved in the highly acidic solution which was caused by the high concentration of H2 ions. Hydrogen gas was generated during the reaction which was seen when bubbles were formed as the penny was dissolved into the beaker.
If the density of the penny had an insignificant percentage of error and was comparable to the density of copper, then the experiment would prove this hypothesis to be
The purpose of this lab was to change pennies from copper to silver to gold, like alchemists have attempted to do in history. Through the data and observations gathered throughout this experiment, it can be concluded that the pennies were not changed into a different element. For example, the density of the penny from 2005; which was the penny that was experimented on to see whether or not it could turn into silver; was 4.62 g/cm3 before the experiment and 4.89 g/cm3 by the end of the experiment. If this copper penny really would have turned into silver, then the density of the penny would be 10.49 g/cm3; which is the density of silver; by the end of the experiment. The penny may have turned silver in color, but this was only because it was plated in the zinc that was added to the beaker of water in the experiment.
Next, a 10 mL beaker is filled with 3 mL of HCl and measure 10 mL of ionized water into a 140 mL beaker. Carefully turn on laboratory burner and start cleaning the Nichrome wire by dipping it into concentrated HCl acid. Hold the Nichrome wire on top of the flame and repeat the step until the wire doesn 't show any color. When the wire is clean, dip the wire again with some of the acid and dip it into the solution with the unknown compound in it. Place the wire back into the flame again and observe the color of the flame.
Copper Cycle Lab Report Ameerah Alajmi Abstract: A specific amount of Copper will undergo several chemical reactions and then recovered as a solid copper. A and percent recovery will be calculated and sources of loss or gain will be determined. The percent recovery for this experiment was 20.46%.
Stoichiometry is a method used in chemistry that involves using relationships between reactants and products in a chemical reaction, to determine a desired quantitative data. The purpose of the lab was to devise a method to determine the percent composition of NaHCO3 in an unknown mixture of compounds NaHCO3 and Na2CO. Heating the mixture of these two compounds will cause a decomposition reaction. Solid NaHCO3 chemically decomposes into gaseous carbon dioxide and water, via the following reaction: 2NaHCO3(s) Na2CO3(s) + H2O(g) + CO2(g). The decomposition reaction was performed in a crucible and heated with a Bunsen burner.
The percent recovery of the copper was calculated using the equation, percent recovery = (the mass of the copper recovered after all the chemical reactions/the initial mass of the copper) x 100. The amount of copper that was recovered was 0.32 grams and the initial mass of the copper was 0.46 grams. Using the equation, (0.32 grams/0.46 grams) x 100 equaled 69.56%. The amount of copper recovered was slightly over two-thirds of the initial amount.
In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis.
(150.22g/mol)(3.5 x 10^-3 mol of nucleophile) = 0.525 g Actual yield = 0.441 g, Percent Yield = (0.441g/0.525g) x 100% = 84% 10. Percent recovery from recrystallization = (0.172g/0.441g) x 100% = 38% 11.
The objectives of this experiment were to use knowledge of chemical formulas and chemical nomenclature to experimentally determine the empirical formula of copper chloride. Common laboratory techniques were used to conduct a reaction between copper chloride and solid aluminum in order to get rid of the water of hydration. The amount of water of hydration in the sample of copper chloride hydrate was calculated by measuring the mass before and after heating the sample. Afterwards, an oxidation-reduction reaction was conducted, resulting in elemental copper.
The final product weight for percent yield was only the solid E product, which missed one half of the final product produce. If both products were weight, the percent yield would have been larger that it was. Instead of 22.33%, it could have been 44.66%. To prove that both products were obtained, but only one of the two products was analyze, a TLC plate of the DCM layer, that contains both products, and of the final product, was obtain.
Empirical Formula of Magnesium Oxide - Lab Report Background Information/Introduction: The aim of this lab is to determine the empirical formula of magnesium oxide by converting magnesium to magnesium oxide. As an alkali earth metal, magnesium reacts violently when heated with oxygen to produce magnesium oxide and magnesium nitride as a byproduct. In order to obtain only magnesium oxide, distilled water was added so that magnesium nitride will react and convert to magnesium hydroxide. Further heating then oxidizes all of the magnesium into magnesium oxide.
The density of the metal object was then calculated using the formula density equals mass divided
Weight a clean, dry, porcelain evaporating dish on the electric balance and record this mass on an appropriate data table. If the crucible needs to be washed before use, then heat the crucible in the Bunsen burner flame for a few minutes and remove any residual water. Then allow it to cool before continuing. Fill the crucible about 1 gram with the hydrated salt and reweight. Assemble the ring stand, ring, clay triangle, and Bunsen burner
Introduction Strong acids and strong acids both dissociate completely in water forming ions. However, strong acids donate a proton to form H3O+ along with a conjugate base and strong bases accept a proton to form OH- along with a conjugate acid. The chemical behavior of acids and bases are opposite. When they are together, their ions cancel out and form a neutral solution. In this experiment, HCl and NaOH will react to form NaOH and H2O with these two steps: The overall reaction is: Both Na+ and Cl- ions combine to form NaCl.