Introduction: The melting point of a pure substance is a characteristic that is physically consistent with each specific substance. When a substance is impure, it causes the melting point to decrease and the range of the melting point to increase. In order to identify a pure substance, it must be purified in order to get an accurate melting point estimation. Purification can be done through crystallization. Crystallization is one of the simplest and most effecting ways to purify a solid. The procedure involves dissolving the impure solid, gravity filtering the hot solution through fluted filter paper to remove impurities and then cooling the filtrate to effect recovery of the material as a solid and then filtered again by suction filtration. …show more content…
o Unknown sample (18) is yellow in color o First time attempting to dissolve, the solution looked like it fully dissolved but once it began to cool, it began to crystallize again boiled again o After adding the charcoal, solution started to turn a mint green color and after heating again the solution became very clear and light green color o Accidently got charcoal in flask when it was being filtered so we filtered it twice o 1st filtration had too much water, crystals did not form when placing flask in ice bath Discussion and Results: When determining the melting point of Benzoic Acid, we observed that the solid began melting at a temperature of 122.6 ºC. Due to this temperature reading we came the conclusion that apparatus #4 has a calibration error of approximately ±0.2 ºC. This error could be due to small impurity of the solid as well as technical malfunctions with the …show more content…
During the gravity filtration, a small amount of charcoal accidently passed through the filter and therefore contaminating our filtered solution. Because of this mistake we needed to repeat the gravity filtration in order to extract the charcoal from the solution. As a result of repeating the filtration and adding an excess amount of water to the solution, when placing our solution in an ice bath, our mixture was unable to crystalize. Because we needed the crystals to form in order to perform the vacuum filtration, we needed to perform the entire crystallization and purification of the experiment once more. After doing so, we observed the crystals form and were able to proceed and perform the vacuum filtration. When weighing our final mass of the solid, we recorded the weight to be 2.20 g which lead to the percent recovery of
Marwah Alabbad Post lab 10/21/15 Question 1: 1. Experiment 1: Number of trails NaOH concentration (M) Volume of HCl solution (mL) Initial volume of NaOH(mL) final volume of NaOH(mL) The volume of NaOH to titrate HCl (mL) Concentration of HCl (M) 1st 0.1023 25.0 10.05 36.12 26.07 0.085 2nd 0.1023 25.0 5.74 31.40 25.66 0.105 3rd 0.1023 25.0 9.84 35.52 25.68 0.105 First trail calculation: 0.02607L× (0.1023mole NaOH/1L)×(1 mol of HCL/1 mol of NaOH)×(1/0.025)= 0.085M of HCl
It also became softer and smaller. Experiment 3: Our group had a bag of crystals and then we put some water in the bag, then we left the bag for a few minutes and then we came back and it was slush. Experiment 4: Our group had a piece of paper and a tub of water and a cup of salt. We put a little bit of the paper into the water with the cup of salt and then we waited a little while
It can be hypothesized that the water in the product affected the melting point
Glacial acetic acid and acetic anhydride were added to the mixture while refluxing, which converted the lime colored solution into a clear mixture. The flask was cooled in an ice bath and the solution
3. Upon adding 20 drops of NaOH, a white precipitate was formed signifying acidic impurity. In the second NaOH mixture, about 20 drops were administered and no precipitate formed indicating that the ample is more pure than before. Data: Weight of flask = 75.10 grams Weight of the flask with solids =
Weighed 1 gram of NaC2H3O2 and mixed it with ionized water. Boiled 12 mL of 1.0M Acetic Acid added into a beaker containing the sodium carbonate on a hot plate until all the liquid is evaporated
Materials and Methods The chemicals used to perform this experiment were distilled water, sodium chloride (NaCl), ice,
The mixture was then distilled. When the temperature was reached to about 59℃, half vial of distillate (1V) and 1 mL of the liquid residue (1L) were collected. For 61.0℃, the distillation was then continued. Samples (2V, 2L) were taken at about 61.0℃.
Introduction: Melting is the change of a solid into a liquid when heat is applied. Melting will occur at a fixed temperature which known as melting point. Melting point is the temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. The temperature will increase until the melting point is reached when heat is applied. Heat will convert the solid into a liquid with no temperature change.
The percent recovery of the copper was calculated using the equation, percent recovery = (the mass of the copper recovered after all the chemical reactions/the initial mass of the copper) x 100. The amount of copper that was recovered was 0.32 grams and the initial mass of the copper was 0.46 grams. Using the equation, (0.32 grams/0.46 grams) x 100 equaled 69.56%. The amount of copper recovered was slightly over two-thirds of the initial amount.
In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis.
3. To purify and identify the product, recrystallization is used in order to purify the product, then melting point and TLC techniques are used to identify the product. Theory 4.
The purpose of this experiment is to successfully grow a crystal. Materials: • Epsom Salt • Food Coloring • Beaker, Small bowl, or Jar Procedure: 1. Bring 1/2 cup of water to a boil. 2.
If impure, preform recrystallization procedure to remove the impurities. Then calculate Percent Recovered on crystals formed, and preform melting point procedure. 2. You find that a solid substance you are trying to purify is very soluble in ethanol, but not very soluble in water. You decide that you are going to try to recrystallize it from a solvent pair, consisting of ethanol and water.
Acids are proton donors in chemical reactions which increase the number of hydrogen ions in a solution while bases are proton acceptors in reactions which reduce the number of hydrogen ions in a solution. Therefore, an acidic solution has more hydrogen ions than a basic solution; and basic solution has more hydroxide ions than an acidic solution. Acid substances taste sour. They have a pH lower than 7 and turns blue litmus paper into red. Meanwhile, bases are slippery and taste bitter.