Identifying a Substance Based on Its Solubility ABSTRACT The basis of this report is to elucidate an experiment where an unknown substance is identified solely based on its solubility. This experiment was conducted in a very lengthy manner due to the precise process of dissolving the unknown substance. It can be inferred that to gain accurate results in the experiment, one must have a developed understanding of how solubility is found. The significance of this experiment is to gain a better understanding of how solubility can be used to identify a substance and correlates to how unknown substances are identified in the real world. During experiments such as this one, it can be easy to misinterpret the identity of a substance when looking at its appearance, which is why it is important to determine the solubility of a substance. …show more content…
For students to better understand the topic they are studying, it is important to demonstrate the idea, this can be done by running a procedure. This lab aids the minds of students by demonstrating the meaning and use of solubility. The identity of an unknown substance can be determined by finding its solubility. It can be known that a substance is soluble in water when it is dissolved. By dissolving a soluble solute in a solvent, the solubility of the created solution can be found. To complete this experiment, it is beneficial to have prior knowledge about solubility and solutions. In this lab experiment, a step-by-step procedure was constructed where an unknown substance was dissolved in water. By doing so, the solubility of the substance was found with the use of the solubility formula and thus, utilizing a solubility chart, the identity of the substance was determined. SAFETY &
The goal of this experiment is to find out what is the identity of the unknown hydrate? To answer this question first, we should know what a hydrate, and how to identify a hydrate using the law of constant proportions. A hydrate is a pure substance because it contains water molecules embedded in its crystal structure that does not vary. By heating the unknown hydrate, we can calculate the mass of the hydrated, and the percentage of water in the hydrate.
As much was conducted throughout this lab, the projected completion of this lab displays that ultimately, the higher the temperature of the water, the faster the dissolving rate of the Alka-Seltzer is. In other words, the hotter the water temperature the quicker the tablet dissolves within the water in regards to the amount of time it took to dissolve. Furthermore, this experiment helps to explain that, if water is taken at a higher temperature and Alka-Seltzer is placed within the water, the Alka-Seltzer will take less time to dissolve because the higher temperatures cause the tablet to melt at a quicker rate. This compares to when Alka-Seltzer is placed in colder temperatures, where instead it takes more time to dissolve, because the lower
In addition, my hypothesis for this lab is the cornstarch and water will make a liquid-solid substance. The Investigating Mixtures Lab objective is to observe that not all liquids behave the same way when mixed with other liquids. Also, my hypothesis for this lab is the vegetable oil will not mix with the water. Conclusion/Analysis:
As the temperature rises the average velocity for the particles increases. This lets them move from one position to another easily. The change in solubility with change in temperature is sometimes used to create solutions with more solute dissolved than predicted by the solubility of the substance. Rock candy is made from a supersaturated solution of sugar.
Because the compound dissolved in water, it is known that the compound is either polar or ionic3. Water is a polar substance, which maximizes its interactions with other polar molecules. Ionic substances also interact with and dissolve in water, because they can be considered an “extreme” case of polarity in which electrostatic forces hold atoms together. The interaction between water and the unknown compound can be described as “dissociation.” When a molecule is dissociated in a polar solvent, the anion of the molecule bonds with the solvent’s cation and vice versa4.
Title: Determining Polarity, Gabriella Anzelc, Mrs. Stockman Objective(s): Comparing the solubility of different compounds and determining their polarity of them based on the solubility. Hypothesis: Create a hypothesis that predicts the polarity of iodine solution, vinegar, vegetable oil, salt, water, and rubbing alcohol. If the compounds (iodine solution, vinegar, vegetable oil, salt, water, and rubbing alcohol) dissolve in water, the compounds are
Mixture Separation October 6, 2015 Sasha Crowley Harrison Rossi Purpose The purpose of the laboratory was to determine the physical properties of four substances, then to separate a mixture of the substances based on their physical properties with limited amounts of materials available. Hypothesis
1. In part A. organic compounds benzophenone was mixed with water after 60 seconds it was determined the compound was insoluble in water. Similarly, to water it was found that hexane which in non polar was semi soluble. The only soluble solvent was methyl alcohol which was detected after 20 seconds.
This lab consisted of determining whether a certain liquid was an acid or base and experimenting with the pH of various substances when either acid or base was added to them. The lab was executed by using two different types of indicators as well as a titration in the end. The first indicator used was litmus paper. Through litmus paper, it is possible to decide whether a liquid is an acid or a base. By placing one slip of red litmus paper by one slip of blue litmus paper and dropping beads of the liquid on each, determining whether the liquid was a base or an acid was possible.
During the Mixed Substances lab the objective was to see how many properties of individual substances compare with properties of mixed substances. From here on the words that would help you along the way of the lab for your research is mixture, homogeneous mixture, and last but least heterogeneous mixture. The hypothesis or guess on what would happen when the water is mixed with the cornstarch, is the cornstarch and water will mix and form a new liquid/solid. However, the Investigating Mixtures lab objective was to observe that not all liquids behave the same way when mixed with other liquids. Moreover the hypothesis of this experiment was that the vegetable oil and colored will separate because the vegetable oil will go to the top and the
I noticed that all 3 different substances provided had a different density. When I put about a ½ inch of the solution “H” it was very thick almost like a jelly consistency. In addition we added another unknown solution “M” into the same test tube that contained the substance “H” we observed that the substance slinked to the bottom of substance “H” and it started creating its own layer. The two layers of solution both did not mix together and was separated by some type of density suspension. Furthermore we introduced another unknown substance “G” This was the densest liquid sinking to the bottom.
You are given a known solid substance with its melting point which has high solubility in hot water and low solubility in cold water. You are assigned the following task: i. Determine if the substance is pure ii. If impure, find a suitable method for its purification by using the given information about the substance How would you proceed, clearly explain your rationale? i. To find if it is a pure substance we see if there is a change in melting point. ii.
Introduction: In this lab, of water in a hydrate, or a substance whose crystalline structure is bound to water molecules by weak bonds, is determined by heating up a small sample of it. By heating, the water of hydration, or bound water, is removed, leaving only what is called an anhydrous compound. Based on the percent water in the hydrate, it can be classified as one of three types: BaCl2O ⋅ 2H20, with a percent water of about 14.57%, CuSO4
The two solvents in the unknown were correctly identified as acetone and toluene. The solvent with the lower boiling point was predicted to be acetone, as its boiling point was observed to be around 59 C, which was closest to the 56.5 C, the ideal boiling point of acetone. This result, however, had the possibility of being incorrect, since the boiling point of methanol, 64.7 C, was relatively close enough to the observed 59 C that methanol could have been incorrectly identified due to experimental errors such as turning the hot plate up too high. A similar situation could have occurred with toluene, the higher boiling point solvent, but this was less likely since there were no possible solvents that had a boiling point that close to toluene. The chromatogram confirmed the identity of the lower boiling point solvent as acetone, and the higher boiling point solvent as toluene.
Bombay: Varghees Publication House, 1990; 171-196. [9]Venkatesh S, Y, Rao V, Anderson B. D, Intrinsic solubility estimation and pH-solubility behavior of cosalane (NSC 658586), an extremely hydrophobic diproticacid, Pharmaceutical Research, 1996; 13(10),