How to Separate Different Mixtures by Taking Advantage of Their Chemical and Physical Traits Badria Al Hosani Grade 10 Chemistry 21st of October 2014 Mrs. Stewart Research question: What is the effect of chemical and physical traits of a substance have on the way its separated? Background This experiment was conducted to determine how to separate mixtures, taking advantage of their chemical and physical traits. The mixture couldn’t be separated in one step, but multiple steps in multiple ways to completely and successfully separate the mixture. Mixtures are physically combined, not …show more content…
Place the beaker containing the wet sand on a hot plate set to “medium.” Heat until the sand appears dry and free flowing, about 5 minutes. Remove the beaker from the hot plate using the beaker tongs and let it sit until cool enough to touch. 12. Determine the mass of the beaker plus sand to the nearest 0.01 g, Record. Analysis Table 1: Quantative Data of Mass Mass of 250-mL beaker 98.35 g Mass of 250-mL beaker + sample 131.77 g Mass of 100-mL beaker 50.34 g Mass of 100-mL beaker + iron filings 52.87 g Mass of 250-mL beaker + dried sand 129.26 Filter paper 2.12 Filter paper with sand 8.19 Table 2: Qualitative Observations of Substances Salt Very tiny pieces of crystal, white Salt-water solution Foggy Iron filings Magnetic, metallic Separated sand Somewhat sticky/clumpy Calculations: First find the mass of a 250 mL beaker only, then get the beaker with the sample and find that mass, then minus the mass of the empty beaker from the beaker with the sample in it, and there’s your answer. Which is 131.77 – 129.26 = 2.55 g of iron filings. Finding percent yield: actual yield/theoretical x 100% Finding percent yield: 2.55/3 x 100% = 86.667 % Finding the amount of iron filings in a 250 mL beaker. Percent of
Objectives In this lab, you will investigate the percent composition by mass of CO2 in Alka-Seltzer® tablets. In addition, you will find out how much CO2 is released into the atmosphere as 2 Alka-Seltzer® tablets chemically react in vinegar. Procedure 250-mL beaker 100-mL graduated cylinder Scale 60 mL of Vinegar 2 Alka-Seltzer® tablets
To separate the Ramos mixture the group first first conducted the dissolve, filter, evaporate method, and prepared the lab for as well. Though for this lab the substance
Next, I removed the water and the quarter from the graduated cylinder and poured 50 mL of water again. I repeated this until I got results for all three coins. To find the volume of each coin, the formula I used was volume of water and coin - initial volume of water ( 50 mL ). To find the density, I divided the mass and the volume of each
Abstract In this experiment the separation of a copper (II) chloride and sodium chloride mixiture was attempted. The main aim was to separate the compounds from eachother while receiving as much of the original mass of both substances as possible - in perfect conditions the original mass will be received after seperation. Many techniques were considered but dissolution, filtration and evaporation proved to be easiest and most reliable in a school environment with school equipment. The copper (II) chloride and sodium chloride mixture was dissolved in a methanol solution and filtered out leaving the sodium chloride behind.
Procedure: With all materials needed, proceed to use the aluminum block to determine the mass and then record in a table. Then fill the graduated cylinder halfway with water and record the volume of the water precisely. Tip the cylinder gradually being cations as not to spill and slide the aluminum block into the graduated cylinder. Put the cylinder straight up and confirm the block is absolutely submerged. Afterwards record the volume.
I. Purpose: To experimentally determine the mass and the mole content of a measured sample. II. Materials: The materials used in this experiment a 50-mL beaker, 12 samples, a balance and paper towels. III.
3. In this experiment, the percent yield was 90%. This number implies that there was little error in this experiment. However, this result could have been caused by certain external factors.
Final idea: Let’s make a watermelon among the substances that we just separated! This is definitely a watermelon now, but why would anyone go through the effort of deconstructing a watermelon in order to reconstruct
In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis.
3. To purify and identify the product, recrystallization is used in order to purify the product, then melting point and TLC techniques are used to identify the product. Theory 4.
Liquid- liquid extraction depends on the solubility of different solutes in immiscible solvents causing organic and aqueous layers. Partitioning coefficient is the ratio of concentration solutes that are in each layer. Deprotonation and protonation of the molecules causes charges to form to distinguish, which solute is in either the organic or aqueous layer. Adjusting pH in the aqueous phase insures that the correct solutes are being recovered. Altering the pH insures that either the solute is going to be in the organic or aqueous phase due to the charges that are form through deprotonation or protonation of the molecule.
Also, although this likely served no contribution in disheveling the results, using a stirrer of the same material to ensure the separate testing of each substance will be as uniform as
A substance can be classified as homogeneous or heterogeneous. A homogeneous mixture is described as having the same properties
The components of the sample called solutes or analytes separate from one another based on their relative vapour. This chromatographic process is called elution.
Introduction Buffer is a solution that resists a change in pH when bases or acid are added. Solutions that are acidic contain high concentrations of hydrogen ions (H+) and have pH values less than seven. Buffer usually consist of a weak acid, and its conjugate base or a weak base and its conjugate acid. The function of buffer is to resist the changes in hydrogen ion concentration as a result of internal and environmental factor. This buffer experiment is important so that we relies the important of buffer in our life.